42 riddle

Here’s a math puzzle for you: can you find four positive integers, like a, b, c, and d, where (1/a) + (1/b) + (1/c) + (1/d) = 1?

For example, if a, b, c, and d all equal 4.

1/1=1 + 1/1=1 + 1/1=1 + 1/1=1=4

But we want an outcome of 1 not 4 and a, b, c and d must have different digits. The Magic to this puzzle is in the number 42!

a=2, b=3, and c=7, then d=42 you can solve the puzzle.

1/2=1 + 1/3=0.33 + 1/7=0.14 + 1/42=0.23 = less than 2 but greater than 1.

I love numbers!

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